Occupations sql hackerrank Jan 10, 2025 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Reload to refresh your session. Advanced Select. We first need to assign a unique number to each row within each occupation. ). Jun 2, 2024 · with doctor as ( select name as name, row_number() over (order by name) as row_num from occupations where occupation = 'doctor' order by name asc ), prof as( select name as name, row_number() over (order by name) as row_num from occupations where occupation = 'professor' order by name asc ), singer as( select name as name, row_number() over I used a similar query, but my order for the professors is incorrect. from occupations) Jul 4, 2022 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. NAME FROM (SELECT OCCUPATION, [NAME], ROW_NUMBER() OVER(PARTITION BY OCCUPATION ORDER BY [NAME] ASC) AS ID FROM OCCUPATIONS WHERE OCCUPATION = 'Doctor') As DocTable FULL OUTER JOIN FROM (SELECT ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) as rn, name, occupation FROM occupations) PIVOT (MAX(name) FOR OCCUPATION IN ('Doctor' as Doctor, Jul 1, 2024 · AS occupation_count_summary FROM occupations GROUP BY occupation ) SELECT result FROM ( SELECT formatted_occupation AS result, 1 AS sort_order FROM OccupationSummary. Occupation = ' Professor '), Finally the code aggregates the rows together using the group by RowNumber and the min statement. Jul 13, 2020 · Occupations. Contribute to ndleah/SQL-Hackerrank-Challenge-Solutions development by creating an account on GitHub. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Sep 25, 2024 · SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name END) AS Actor FROM ( SELECT name, occupation, ROW_NUMBER() OVER Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. select [Doctor] as Doctor, [Professor] as Professor, [Singer] as Singer, [Actor] as Actor from (select name, occupation, ROW_NUMBER() OVER ( PARTITION BY Occupation ORDER BY Jun 3, 2024 · SELECT MAX(CASE WHEN occupation='doctor' THEN NAME ELSE NULL END) AS doctor, MAX(CASE WHEN occupation='professor' THEN NAME ELSE NULL END) AS professor, MAX(CASE WHEN occupation='singer' THEN NAME ELSE NULL END)AS singer, MAX(CASE WHEN occupation='actor' THEN NAME ELSE NULL END)AS actor FROM ( . select doctor, professor, singer, actor . WITH LEBALTABLE AS Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. But join keyword is not working in this hackerrank. Select MAX(CASE WHEN Occupation = 'Doctor' Then Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' Then Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' Then Name END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' Then Name END) AS Actor FROM ( Select *, ROW_NUMBER() OVER SQL. r2, a. Name ASC) RowNum FROM OCCUPATIONS o WHERE o. Occupation = b. I translated your solution to something that works in MS SQL. Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Codes of Algorithms/Coding Competitions on Hackerrank with Python, JavaScript, C++ and SQL - ynyeh0221/HackerRank SELECT CONCAT(GROUP_CONCAT(IF(Occupation = 'Doctor', Name, NULL) ORDER BY Name SEPARATOR ',')) AS Doctor, CONCAT(GROUP_CONCAT(IF(Occupation = 'Professor', Jul 13, 2020 · Occupations. SELECT Occupation, MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Aug 6, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. name, rank() over( order by P. name) Dr from occupations D where occupation = 'Doctor'), Ss As(select S. So you obtain something like: Eve | Actor |1 Jennifer |Actor |2 Ketty | Actor |3 Samantha |Actor |4 Aamina |Doctor|1 Julia |Doctor|2 Priya |Doctor |3 And so on for the other professions. Easy SQL (Intermediate) Max Score: 30 Success Rate: 94. May 10, 2024 · SQL. if it is wrong, let me know~ ^^. WITH CTE AS ( SELECT Occupation, Name, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' Jan 4, 2023 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. Except for it's giving Occupation name as the 1st column, I don't understand why this is not working, can some explain please. Most ones can solve the problem but i can't. Jun 27, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. In the first statement it doesn't matter if Min or Max is used as long as the occupations are ordered by Name, they are used to select actual values rather than NULL. Sep 30, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Oct 10, 2024 · WITH ctc AS (SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS row_num FROM occupations ) SELECT MAX(CASE WHEN occupation ='Doctor' THEN name END)AS Doctor, MAX(CASE WHEN occupation ='Professor' THEN name END)AS Professor, MAX(CASE WHEN occupation ='Singer' THEN SQL. In this SELECT Statement im grabbing Names, Occpation and Row_Numer counts Ordering by Name as the problem asks i. Solve Challenge. :) For those of you who do not get how to number the rows, just think of it as : the first Doctor i. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. See more Annotated solutions to HackerRank's SQL domain questions. - SQL-Hackerrank-Challenge-Solutions/Advanced Select/Occupations. WITH RankedOccupations AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS rn FROM OCCUPATIONS ) Jun 8, 2024 · (select case when occupation = 'doctor' then name end as 'doctor', case when occupation = 'professor' then name end as 'professor', case when occupation = 'singer' then name end as 'singer', case when occupation = 'actor' then name end as 'actor', row_number() over (partition by occupation order by name) as n. Create a HackerRank account Feb 6, 2023 · Firstable, you use ROW_NUMBER() to order the names with the same profession. Jan 27, 2024 · -- Step 1: Assigning Row Numbers within each Occupation WITH NameLists AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS NameOrder FROM Occupations ) You signed in with another tab or window. Great explanation. Means When it finds actor it increments the value a for doctor it increments the value d for professor it increments the value p for singer it increments the value s then I used group by so that I can combine the all for count parallely means by this I wanna show the first of all the occupation's name together so that it can take a proper table form. Contribute to edaaydinea/HackerRank development by creating an account on GitHub. Oct 22, 2024 · WITH doctors AS (SELECT name AS doctorName, ROW_NUMBER OVER (PARTITION BY OCCUPATION ORDER BY name) AS rn FROM OCCUPATIONS WHERE occupation = ' Doctor '), professors AS (SELECT name AS professorName, ROW_NUMBER OVER (PARTITION BY OCCUPATION ORDER BY name) AS rn FROM OCCUPATIONS mysql version : SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name ELSE NULL END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name ELSE NULL END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name ELSE NULL END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' THEN Name ELSE NULL END) AS Actor Aug 18, 2024 · SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE NULL END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE NULL END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE NULL END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name ELSE NULL END) AS Actor FROM Sep 3, 2023 · My SQL Server solution, using PIVOT and CTE :- WITH numbered_names ( Name , Occupation , RN ) AS ( SELECT Name , Occupation , ROW_NUMBER () OVER ( PARTITION BY Occupation ORDER BY Name ) AS RN FROM Occupations ) SELECT Doctor , Professor , Singer , Actor FROM numbered_names PIVOT ( MAX ( Name ) Dec 20, 2024 · MAX is used to pick the name in a grouped row. Mar 18, 2023 · SQL. Name, ROW_NUMBER OVER (ORDER BY o. The output Jan 3, 2024 · /*Solution with Oracle Sql*/ WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) Feb 24, 2024 · I think this is a much simpler MySQL solution: CREATE VIEW OccupationsView AS SELECT ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS row_num, Occupation, Name FROM OCCUPATIONS; SELECT MAX(IF(Occupation = 'Doctor', Name, NULL)) AS Doctor, MAX(IF(Occupation = 'Professor', Name, NULL)) AS Professor, For me it always helps to turn the "subquery" into its own query and take a look at its output, as follows: SELECT Name, Occupation, (ROW_NUMBER() OVER( PARTITION BY Occupation ORDER BY Name )) AS rn FROM Occupations Jan 3, 2024 · /*Solution with Oracle Sql*/ WITH RankedOccupations AS ( SELECT NAME, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' THEN Name END) You signed in with another tab or window. Sep 24, 2024 · SQL. SQL. Problem. MS sql server. actor from (SELECT b. 50%. Apr 14, 2024 · MY SQL Solution. These recursive functions you constructed {@r1:=@r1+1} is basically the same as creating a rank column partitioned by Occupation:with cte as ( select RANK() OVER (PARTITION BY Occupation ORDER BY Name) as Rank, case when Occupation='Doctor' then Name else null end as May 17, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. UNION ALL SELECT occupation_count_summary, 2 FROM TotalOccupationCount Jul 5, 2024 · MYSQL: this code contains 2 CTEs, first grouping by occupation and numbering names by alphbetical order second CTE It uses a CASE statement within the MAX function to conditionally aggregate names based on the Occupation. Jul 30, 2024 · with temp as (select* ,ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS id from OCCUPATIONS ) , pvt_temp as (select * From temp pivot (max(name) for occupation in (Doctor, Professor, Singer, Actor) )as pvtCols )select Doctor, Professor, Singer, Actor from pvt_temp Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. You signed out in another tab or window. Occupations. Julia gets a rownumber = 2 , and so on. name) Sr from occupations S where occupation = 'Singer'), AA As Name ASC) RowNum FROM OCCUPATIONS o), Doctors AS (SELECT o. Hiring developers? Log In; Sign Up; Prepare. Nov 30, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Simply i wrote this code in SQL Server and its working fine: Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. doctor, b. name, rank() over( order by S. from (select name, occupation, rownumber() over (partition by occupation order by name asc) rn from occupations) May 8, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Name) AS rank FROM Occupations AS a I guess the row number function provides each distinct occupation with separate row numbers, like 1,2,3 for doctor and again 1,2,3 for professor since it was partitioning by occupation. Step 1: Number the rows within each occupation. You are viewing a single comment's thread. Join over 23 million developers in solving code challenges on HackerRank, one of the best ways to prepare for programming interviews. chat-gpt will refers you dynamic queries or some ways like my query because there is no pivot operator like Microsoft SQL Server in MySQL. May 3, 2023 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Solved. In mysql: select Doctor, Professor, Singer, Actor. I am using idn to combine the result properly. Name, (SELECT COUNT(*) FROM Occupations AS b WHERE a. Jun 30, 2023 · The goal is to transform the data from a single Occupation column to multiple columns: Doctor, Professor, Singer, and Actor, with names listed underneath each occupation and sorted alphabetically. NAME, ProfTable. select Doctor, Professor, Singer, Actor from (select *, row_number () Create a HackerRank account WITH partitioned_cte AS (SELECT Name, Occupation, row_number OVER(PARTITION BY Occupation ORDER BY Name) AS name_group_rank FROM OCCUPATIONS) SELECT (SELECT Name FROM partitioned_cte WHERE Occupation = 'Doctor' AND name_group_rank = t. 4 days ago · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Submissions. professor,f. Occupation = ' Doctor '), Professors AS (SELECT o. Apr 28, 2024 · WITH t1 AS (SELECT name AS doctor, ROW_NUMBER OVER (ORDER BY name) AS row_num FROM occupations WHERE occupation = ' Doctor '), t2 AS (SELECT name AS professor, ROW_NUMBER OVER (ORDER BY name) AS row_num FROM occupations WHERE occupation = ' Professor '), t3 AS (SELECT name AS singer, ROW_NUMBER OVER Nov 8, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. e Alice Doctor 1 Sam Doctor 2 Juile Singer 1 Zach Singer 2 etc. Note: Print NULL when there are no more names corresponding to an Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Oracle. Jul 20, 2024 · SET @max_rows:= (SELECT COUNT(DISTINCT Occupation) FROM OCCUPATIONS);. Leaderboard. Source: HackerRank. Learn how to solve the Occupations problem in SQL using MySQL set and case statements. May 2, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. sql at master · ynyeh0221/HackerRank Oct 24, 2024 · This approach is easy to use and understandable. so to get the value of pivot column, we have to use 'min'. Discussions. name_group_rank), (SELECT Name FROM partitioned_cte WHERE Occupation = Mar 29, 2024 · SQL Server WITH DOCTOR AS ( SELECT NAME , ROW_NUMBER () OVER ( ORDER BY NAME ASC ) NUM FROM OCCUPATIONS WHERE OCCUPATION = ' DOCTOR ' GROUP BY NAME ), PROFESSOR AS ( SELECT NAME , ROW_NUMBER () OVER ( ORDER Solutions for all SQL challenges on HackerRank executed on MySQL and MS SQL Server. Works with Mysql: # with base_tab as ( select case when occupation ='Doctor' then name else null end as doctor, case when occupation='Professor' then name else null end as professor, case when occupation='Singer' then Name else null end as singer, case when Occupation='Actor' then Name else null end as actor from OCCUPATIONS), doctor_tab as ( select row_number() Jan 23, 2023 · Hi All, could anyone support me to know why the below query is wrong? SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE 'NULL' END) Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE 'NULL' END) Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE 'NULL' END) Singer, MAX(CASE WHEN occupation Jun 28, 2023 · With CTE as (SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) as rn from Occupations) Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Input Format. So add Jul 11, 2024 · WITH ranked AS ( SELECT name, occupation, ROW_NUMBER() OVER (PARTITION BY occupation ORDER BY name) AS rn FROM OCCUPATIONS ), pivoted AS ( SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN Sep 11, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SQL (Basic) SQL (Intermediate) SQL (Advanced) Difficulty. The output column headers should be Doctor, Professor, Singer, and Actor, respectively. SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, MAX(CASE WHEN Dec 24, 2024 · MYSQL SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name END) AS Actor FROM ( SELECT name, occupation, @rownum:= Nov 25, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Occupation AND a. Jenny Ashley Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. name, rank() over( order by D. @arati1626 @himanshimathpal1 To clarify this, first you need to create row number of each record partitioned by its occupation in the entity Nov 26, 2024 · select e. Create a HackerRank account Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Jul 4, 2024 · MySQL: SELECT MAX(CASE WHEN Occupation = 'Doctor' Then Name END) AS 'Doctor', MAX(CASE WHEN Occupation = 'Professor' Then Name END) AS 'Professor', MAX(CASE WHEN Occupation = 'Singer' Then Name END) AS 'Singer', MAX(CASE WHEN Occupation = 'Actor' Then Name END) AS 'Actor' FROM (SELECT Name, Occupation, Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Dec 30, 2024 · with cte as (select *, row_number over (partition by Occupation order by Name) as ct from Occupations) select min (case when Occupation = ' Doctor ' then Name else null end) as ' Doctor ', min (case when Occupation = ' Professor ' then Name else null end) as ' Professor ', min (case when Occupation = ' Singer ' then Name else null end) as Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. WITH RankedOccupations AS ( -- Assign a row number to each name based on their occupation and sort them alphabetically SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS RowNumber FROM OCCUPATIONS ) -- Pivot the table by occupations SELECT Ex: #237 [Solved] Occupations in SQL solution in Hackerrank Intermediate Ex: #238 [Solved] Binary Tree Nodes in SQL solution in Hackerrank Intermediate Yes, little bit harder for me too :-) This query creates the ranking value, smaller values are in alphabetical order. Occupation, a. Apr 19, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Create a HackerRank account Group by is used to convert columns to rows. NAME, ActTable. Mar 13, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Here, we have columns- name, occupation and rank (generated for each occupation using ROW_NUMBER() function) Since 1st it is partitioned by occupation, it gives values sorted in asc order according to occupation and then sorts the names HackerRank SQL track solutions. Dec 25, 2022 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Aamina gets a rownumber = 1, the second Doctor i. Once you complete step 3, add "ORDER BY Name" (Refer above code on where to add Order by clause). Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. See the input, output, and explanation of the problem, and the code solution provided by CodingBroz. Create a HackerRank account Jul 23, 2024 · SELECT MAX(CASE WHEN occupation = 'doctor' THEN name ELSE NULL END) AS doctor, MAX(CASE WHEN occupation = 'professor' THEN name ELSE NULL END) AS professor, MAX(CASE WHEN occupation = 'singer' THEN name ELSE NULL END) AS singer, MAX(CASE WHEN occupation = 'actor' THEN name ELSE NULL END) AS actor FROM ( May 13, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Note: Print NULL when there are no more names corresponding to an occupation. Sample Output. Jul 23, 2024 · WITH RankedOccupations AS ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) AS rn FROM OCCUPATIONS ) SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = SQL. I use this query With Ps As (select P. i think so, i know group by is working with aggregate functions(min, max, count, etc. Unsolved. Medium. Sql Server. The output should consist of four columns (Doctor, Professor, Singer, and Actor) in that specific order, with their respective names listed alphabetically under each column. Really good stuff. The below SQL query works fine on SQL Server. Apr 3, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. . right? i'm easy member too. The OCCUPATIONS Jul 1, 2024 · AS occupation_count_summary FROM occupations GROUP BY occupation ) SELECT result FROM ( SELECT formatted_occupation AS result, 1 AS sort_order FROM OccupationSummary. UNION ALL SELECT occupation_count_summary, 2 FROM TotalOccupationCount Apr 16, 2023 · SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name ELSE NULL END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name ELSE NULL END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name ELSE NULL END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' THEN Name ELSE NULL END) AS Actor Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Dec 3, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Skills. Then same property I need in result is rollnumber . Name) AS rank FROM Occupations AS a Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective This repository includes HackerRank Solutions. The output column headers should be Doctor, Professor, Singer, Mar 2, 2021 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. PARTITION BY Occupation: Resets the row number for each occupation group. ROW_NUMBER(): Assigns a unique number to each row. Yes, little bit harder for me too :-) This query creates the ranking value, smaller values are in alphabetical order. THIS IS FOR SQL SERVER SELECT [Doctor],[Professor],[Singer],[Actor] FROM( SELECT ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY NAME) AS [ROWNUMBER], * FROM OCCUPATIONS) AS Dec 20, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. sql at main · qanhnn12/SQL-Hackerrank-Challenge-Solutions Jan 5, 2025 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. //This will return Max of each row number (each row number will have only 1 occupations and rest will be null)// Select Max(case when occupation='Doctor' then name end) as Doctor, Max(case when occupation='Professor' then name end) as Professor, Max(case when occupation='Singer' then name end) as Singer, Max(case when occupation='Actor' then Jan 10, 2025 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. name) Pr from occupations P where occupation = 'Professor') , Ds As (select D. row2: the second in Doctor; the secondin Professor; the second in Singer; the second in Actor. MS SQL Code: SELECT Doctor, Professor, Singer, Actor FROM ( SELECT Name, Occupation, ROW_NUMBER() OVER (PARTITION BY Occupation ORDER BY Name) as rn FROM Occupations ) AS src_table PIVOT ( MAX(Name) Nov 28, 2023 · WITH RankedNames AS ( SELECT Name, OCCUPATION, ROW_NUMBER() OVER (PARTITION BY OCCUPATION ORDER BY Name) AS NameRank FROM OCCUPATIONS ) SELECT MAX(CASE WHEN OCCUPATION = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN OCCUPATION = 'Professor' THEN Name END) AS Professor, Dec 24, 2024 · in SQL SERVER, code is . Hard. Easy. professor FROM (SELECT name AS doctor, ROW_NUMBER() OVER (ORDER BY name) AS r1 FROM occupations WHERE occupation = 'doctor' ) AS a right join (SELECT name AS professor, ROW_NUMBER() OVER (ORDER BY name) AS r2 FROM occupations WHERE For example, when you group by ID 1, you will get the first row with occupation "Doctor", and the first row with occupation "Singer" and so on with the other two occupations, this will force the correct values to come first. Create a HackerRank account Be part of a 23 million-strong community of developers. 0 | Create a HackerRank account Problem. The output column headers should be Dec 28, 2022 · Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. You mister just saved my day. I'm new to SQL and struggled to find the solution for about 2 days in my spare time. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Nov 17, 2024 · SELECT MIN (CASE WHEN occupation = ' Doctor ' THEN name END) AS Doctor, MIN (CASE WHEN occupation = ' Professor ' THEN name END) AS Professor, MIN (CASE WHEN occupation = ' Singer ' THEN name END) AS Singer, MIN (CASE WHEN occupation = ' Actor ' THEN name END) AS Actor--You can use MIN or MAX up to you b / c It doesn ' t effect Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Note: Print NULL when there are no more names May 4, 2024 · with d as (select name, row_number over as id from occupations where occupation = ' doctor ' order by name), p as (select name, row_number over as id from occupations where occupation = ' professor ' order by name), s as (select name, row_number over as id from occupations where occupation = ' singer ' order by name), a as (select name, row Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. As stated below 'min()/max() will return a name for specific index and specific occupation. SELECT DocTable. We use cookies to Nov 29, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. SELECT a. Oct 8, 2024 · this will work for oracle sql : SELECT MAX(CASE WHEN occupation = 'Doctor' THEN name ELSE NULL END) AS Doctor, MAX(CASE WHEN occupation = 'Professor' THEN name ELSE NULL END) AS Professor, MAX(CASE WHEN occupation = 'Singer' THEN name ELSE NULL END) AS Singer, MAX(CASE WHEN occupation = 'Actor' THEN name ELSE Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. Codes of Algorithms/Coding Competitions on Hackerrank with Python, JavaScript, C++ and SQL - HackerRank/Occupations. You switched accounts on another tab or window. Do you know anything about JOIN here? 0 | Parent Permalink. Name > b. Since some of us here may not be fimilar with sql, I'll start with where I left so you get the whole picture. We use cookies to ensure you have the best browsing experience on our website. Oct 24, 2024 · Pivot the Occupation column so the Name of each person in OCCUPATIONS is displayed underneath their respective Occupation. - raleighlittles/HackerRank-SQL /* Pivot the Occupation column in OCCUPATIONS so that each Name is sorted alphabetically and displayed underneath its corresponding Occupation. NAME, SingTable. e. The output column headers should be Doctor, Professor, Singer, and Actor, Jul 23, 2023 · HackerRank SQL Interview Question: Level Medium. singer,f. I even can understand the answer given in discussion section. In my solution I have solved it but my solution is not flexible but It is very easy to understand let me explain you here in the question I have constructed 4 new tables each tables consisting of names of specific occupation and rno which contains the serial number of record. Status. Create a HackerRank account Dec 16, 2024 · SELECT MAX(CASE WHEN Occupation = 'Doctor' THEN Name END) AS Doctor, MAX(CASE WHEN Occupation = 'Professor' THEN Name END) AS Professor, MAX(CASE WHEN Occupation = 'Singer' THEN Name END) AS Singer, MAX(CASE WHEN Occupation = 'Actor' THEN Name END) AS Actor FROM ( SELECT Name, Occupation, ROW_NUMBER() Sep 9, 2024 · Step2 : Recombine rows : use group by (need at least one same property ) Because we want the result looks like this row1: the first in Doctor; the first in Professor; the first in Singer; the first in**Actor**. Apr 27, 2024 · Here I see the answer is quite tough for me to solve. doctor,e. ably nkel ofkzei ttyx ftiui csparg cmkmd todgt xev iye